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<?xml-stylesheet type="text/xsl" href="https://devzone.nordicsemi.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>How to get every adc channel conversion result?</title><link>https://devzone.nordicsemi.com/f/nordic-q-a/10314/how-to-get-every-adc-channel-conversion-result</link><description>Hi: I want use all eight ADC channel, But I don&amp;#39;t know how to get different channel conversion result. 
 I write my code as follow: 
 void adc_config(void)
 
 {
const nrf_adc_config_t nrf_adc_config =
{
ADC_CONFIG_RES_10bit,
NRF_ADC_CONFIG_SCALING_INPUT_ONE_THIRD</description><dc:language>en-US</dc:language><generator>Telligent Community 13</generator><lastBuildDate>Wed, 18 Nov 2015 08:11:01 GMT</lastBuildDate><atom:link rel="self" type="application/rss+xml" href="https://devzone.nordicsemi.com/f/nordic-q-a/10314/how-to-get-every-adc-channel-conversion-result" /><item><title>RE: How to get every adc channel conversion result?</title><link>https://devzone.nordicsemi.com/thread/38283?ContentTypeID=1</link><pubDate>Wed, 18 Nov 2015 08:11:01 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:0f96e5db-8b4b-482f-b9ad-5d071480fb80</guid><dc:creator>atune</dc:creator><description>&lt;ol&gt;
&lt;li&gt;
&lt;p&gt;Probably not although you&amp;#39;re not showing the entire code. You need to first input_select, then adc_start and then wait for the interrupt to get the result. Then select another channel, start conversion, wait for interrupt... You can&amp;#39;t select every channel at once.&lt;/p&gt;
&lt;/li&gt;
&lt;li&gt;
&lt;p&gt;You can use &lt;a href="http://infocenter.nordicsemi.com/topic/com.nordic.infocenter.sdk51.v10.0.0/group__nrf__adc.html#ga23c9071d2c15461db6bf6c8a144339b8"&gt;nrf_adc_convert_single&lt;/a&gt; to get results from each channel in succession without interrupts.&lt;/p&gt;
&lt;/li&gt;
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