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<?xml-stylesheet type="text/xsl" href="https://devzone.nordicsemi.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>AIN to 8-bit accuracy to reduce the leakage current</title><link>https://devzone.nordicsemi.com/f/nordic-q-a/117955/ain-to-8-bit-accuracy-to-reduce-the-leakage-current</link><description>I refer to and the answer answer given by AI referring me to you. 
 
 I need the lithium battery only to about 8-bit accuracy to reduce the leakage current. Please provide the recalculated values for R1, R2 and Cext, and the new reduced leakage current</description><dc:language>en-US</dc:language><generator>Telligent Community 13</generator><lastBuildDate>Tue, 14 Jan 2025 08:35:31 GMT</lastBuildDate><atom:link rel="self" type="application/rss+xml" href="https://devzone.nordicsemi.com/f/nordic-q-a/117955/ain-to-8-bit-accuracy-to-reduce-the-leakage-current" /><item><title>RE: AIN to 8-bit accuracy to reduce the leakage current</title><link>https://devzone.nordicsemi.com/thread/518238?ContentTypeID=1</link><pubDate>Tue, 14 Jan 2025 08:35:31 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:819feadc-b046-4776-b087-7c25726e04b1</guid><dc:creator>Priyanka</dc:creator><description>&lt;p&gt;Hi,&lt;br /&gt;&lt;br /&gt;&lt;/p&gt;
&lt;p&gt;According to the blog, you should be able to use the same resistances of 4M&lt;span&gt;Ω and 10MΩ respectively, or you could even use higher resistances like 8MΩ and 20MΩ.&amp;nbsp;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span&gt;From the blog, you can calculate Cext like:&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;strong&gt;Cext = Csample * (2 ^ your bit resolution)&lt;/strong&gt;&lt;/p&gt;
&lt;p&gt;So your Cext = Csample * 2^8 = 640pF. You can use any standard value, say 680pF.&lt;/p&gt;
&lt;p&gt;And your maximum leakage current should now be 4.2 / (8MΩ + 20MΩ) = 150nA&lt;/p&gt;
&lt;p&gt;Regards,&lt;br /&gt;Priyanka&lt;/p&gt;
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