Help with SHIPHOLD Pressed and Released Events on NPM1300 + STM32L4 + npmx

RE: Help with SHIPHOLD Pressed and Released Events on NPM1300 + STM32L4 + npmx

GT — Fri, 04 Jul 2025 12:46:43 GMT

Hi Kennet,

Spot on - everything is working as expected now. Looking back, it was an obvious mistake in hindsight.

Thank you very much for your support. Have a great weekend!

Regards,
Georgi

RE: Help with SHIPHOLD Pressed and Released Events on NPM1300 + STM32L4 + npmx

Kenneth — Thu, 03 Jul 2025 14:31:22 GMT

Hi again,

I got some feedback.

pmx_core_event_interrupt_enable(&m_pmic, NPMX_EVENT_GROUP_SHIPHOLD, 
                                NPMX_EVENT_GROUP_SHIPHOLD_PRESSED_MASK | 
                                NPMX_EVENT_GROUP_SHIPHOLD_RELEASED_MASK);

This is the correct way of enabling the interrupt. Call this function once per event group. The masks should be OR'ed together to enable the interrupts you want within that group.

If you call this function multiple times in a row with the same event group, the new event mask will overwrite the old one in the driver state logic, but the driver will not disable this event from being generated by the PMIC. So you can get into situations such as the one described.

[quote user=""]As I understand it, npmx_core_proc() should clear all the pending interrupt flags and report back the mask— is that correct?[/quote]

This is correct. As long as npmx is informed that the interrupt signal pin is asserted via npmx_core_interrupt(), which seems to be the case in this code.

Could you try calling npmx_core_interrupt(&m_pmic) for every iteration of the main loop? This will force npmx to keep checking the event registers.

Kenneth

RE: Help with SHIPHOLD Pressed and Released Events on NPM1300 + STM32L4 + npmx

GT — Thu, 03 Jul 2025 08:15:25 GMT

Hi Kenneth. Thanks for that. Let me know if you need any additional details.

RE: Help with SHIPHOLD Pressed and Released Events on NPM1300 + STM32L4 + npmx

Kenneth — Wed, 02 Jul 2025 11:17:25 GMT

Hi,

Let me ask internally and get back to you.

Kenneth