https://devzone.nordicsemi.com/f/nordic-q-a/12994/no-start-bit-in-uart-nrf51822Dear all, I make a simple test on the UART0, putting the code in &#39;simple_uart.c&#39; to my main.c. When I send out a character &#39;A&#39;, 0x41. From the CRO timing, it appears that the START bit is lost. Please help as the receiver MCU cannot extract the dataen-USTelligent Community 13Tue, 05 Apr 2016 14:49:24 GMThttps://devzone.nordicsemi.com/thread/49517?ContentTypeID=1Tue, 05 Apr 2016 14:49:24 GMT137ad170-7792-4731-bb38-c0d22fbe4515:4a211a14-d1b1-40d4-aee1-cadb6d565338Manuel Kwong<p>wrong on the endian arrangement, the waveform is correct, problem solved.</p><div style="clear:both;"></div>https://devzone.nordicsemi.com/thread/49516?ContentTypeID=1Tue, 05 Apr 2016 13:09:51 GMT137ad170-7792-4731-bb38-c0d22fbe4515:467ee727-fab4-4f3f-b68f-a27cedd2ef4eManuel Kwong<p>Dear awneil,</p> <p>Picture is attached above, the delta t is 1.874ms and it is 9 bit data with my setting being 4800 baudrate (using the constant provided in nrf51_bitfields.h: #define UART_BAUDRATE_BAUDRATE_Baud4800 (0x0013B000UL) /*!&lt; 4800 baud. */ it is correct setting to be 4800. My data sending out is 0x41, so the first bit &#39;0&#39; is data bit, not start bit but adding the 9th bit at trail. It is strange that I set the CONFIG register to be 0x00.</p><div style="clear:both;"></div>https://devzone.nordicsemi.com/thread/49515?ContentTypeID=1Tue, 05 Apr 2016 10:05:00 GMT137ad170-7792-4731-bb38-c0d22fbe4515:d834ecdb-2564-44aa-a2c5-25578c2ab27cawneil<p>What makes you say that the start bit is lost?</p> <p>Can you post an oscilloscope or logic analyser plot of the signal?</p> <p>Are you sure you have correctly configured the baud rate ... ?</p><div style="clear:both;"></div>