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<?xml-stylesheet type="text/xsl" href="https://devzone.nordicsemi.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Pull-up current usage</title><link>https://devzone.nordicsemi.com/f/nordic-q-a/20427/pull-up-current-usage</link><description>In an answer to this question about current usage of pull-ups here , RK and Vidar comment: 
 
 Is the GPIO you have configured as a pull up, being pulled down? If so you&amp;#39;d expect to see 3v or so across the 15k or so pull up resistor which is about 200uA</description><dc:language>en-US</dc:language><generator>Telligent Community 13</generator><lastBuildDate>Wed, 15 Mar 2017 16:18:48 GMT</lastBuildDate><atom:link rel="self" type="application/rss+xml" href="https://devzone.nordicsemi.com/f/nordic-q-a/20427/pull-up-current-usage" /><item><title>RE: Pull-up current usage</title><link>https://devzone.nordicsemi.com/thread/79638?ContentTypeID=1</link><pubDate>Wed, 15 Mar 2017 16:18:48 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:d85538ff-d6a7-44c6-97f6-772423f98012</guid><dc:creator>Stian R&amp;#248;ed Hafskjold</dc:creator><description>&lt;ul&gt;
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&lt;p&gt;If the GPIO is configured with a pull-up, and not being pulled to GND, there will not flow any current through the resistor, and therefore it will not consume 200µA.&lt;/p&gt;
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&lt;p&gt;If you configure the input as sense low with a pull-up, current will only flow when you pull the pin down, i.e. to wake up the chip. (or vice versa)&lt;/p&gt;
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