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<?xml-stylesheet type="text/xsl" href="https://devzone.nordicsemi.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>nRF52832 analog input high-Z</title><link>https://devzone.nordicsemi.com/f/nordic-q-a/22093/nrf52832-analog-input-high-z</link><description>Hello, 
 I&amp;#39;m designing a project with the nRF52832 where I will use an external SPI ADC.
For debug and backward compatibility purposes, I also plan to use the SAADC.
The analog input will be connected to both the SPI ADC and the SAADC (in parallel</description><dc:language>en-US</dc:language><generator>Telligent Community 13</generator><lastBuildDate>Tue, 16 May 2017 13:58:49 GMT</lastBuildDate><atom:link rel="self" type="application/rss+xml" href="https://devzone.nordicsemi.com/f/nordic-q-a/22093/nrf52832-analog-input-high-z" /><item><title>RE: nRF52832 analog input high-Z</title><link>https://devzone.nordicsemi.com/thread/86814?ContentTypeID=1</link><pubDate>Tue, 16 May 2017 13:58:49 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:54af1e02-1d0f-4f3a-ae86-7906bd901732</guid><dc:creator>Michael</dc:creator><description>&lt;p&gt;Thanks Jørn.
The 500 MOhms of the ADC is due to an integral input amplifier which provides a buffer thus showing a constant input impedance.
If the input impedance of the analog inputs is in fact 10 MOhms, it might be something I can live with.
Thanks,
Michael.&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: nRF52832 analog input high-Z</title><link>https://devzone.nordicsemi.com/thread/86815?ContentTypeID=1</link><pubDate>Tue, 16 May 2017 13:57:09 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:2cb64c7e-3dfc-4b4d-838c-35f64fcb769a</guid><dc:creator>Turbo J</dc:creator><description>&lt;blockquote&gt;
&lt;p&gt;is the input impedance of the analog inputs 1 Megaohms no matter what?&lt;/p&gt;
&lt;/blockquote&gt;
&lt;p&gt;I would assume that the input is 1 MOhm no matter what. Remember that the NRF52x has no &lt;em&gt;dedicated&lt;/em&gt; analog pins, so there might be some resitual current from the GPIO part even when it is disabled.&lt;/p&gt;
&lt;p&gt;And there is still an analog multiplexer present that switches inputs to the analog peripherials (SAADC, COMP, LPCOMP).&lt;/p&gt;
&lt;p&gt;Those 0-R resistors are tiny in a 01005 package.&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: nRF52832 analog input high-Z</title><link>https://devzone.nordicsemi.com/thread/86813?ContentTypeID=1</link><pubDate>Tue, 16 May 2017 13:50:15 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:7360d946-5124-4880-999c-8449fa528600</guid><dc:creator>J&amp;#248;rn</dc:creator><description>&lt;p&gt;Hello Michael&lt;/p&gt;
&lt;p&gt;The 1 MOhm resistor seen in the schematic &lt;a href="http://infocenter.nordicsemi.com/topic/com.nordic.infocenter.nrf52832.ps.v1.1/saadc.html?cp=2_2_0_36_11_0#unique_717931571"&gt;here&lt;/a&gt; is a parasitic resistance equivalent caused by current leakage in the ESD structure and will be there regardless. It is not specified as 1MOhm, but as at least 1MOhm. I have been informed by a member of our design team the actual resistance is &amp;gt;10MOhm, and not &amp;gt;1MOhm as stated in the product specification. It is not a fixed resistance and it will vary as a function of temperature. The moment you sample the TACQ switch will close, and the capacitor will provide a low resistance path and draw current. It is important the acquisition time is set long enough to allow the capacitor to settle. Please see &lt;a href="http://infocenter.nordicsemi.com/topic/com.nordic.infocenter.nrf52832.ps.v1.1/saadc.html?cp=2_2_0_36_8#concept_qh3_spp_qr"&gt;this section&lt;/a&gt;&lt;/p&gt;
&lt;p&gt;I would think the 500 MOhms of your ADC is when the ADC is not sampling, and during sampling it would present a low impedance which would then be the dominant impedance in the parallel coupling.&lt;/p&gt;
&lt;p&gt;Best regards&lt;/p&gt;
&lt;p&gt;Jørn Frøysa&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item></channel></rss>