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<?xml-stylesheet type="text/xsl" href="https://devzone.nordicsemi.com/cfs-file/__key/system/syndication/rss.xsl" media="screen"?><rss version="2.0" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:slash="http://purl.org/rss/1.0/modules/slash/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:atom="http://www.w3.org/2005/Atom"><channel><title>Estimation of battery life while only advertising.</title><link>https://devzone.nordicsemi.com/f/nordic-q-a/35072/estimation-of-battery-life-while-only-advertising</link><description>Hi there .. 
 I have question regarding estimation of a coin cell battery life while advertising on nrf52840 PDK. I followed here https://devzone.nordicsemi.com/b/blog/posts/nrf52-online-power-profiler to compute the average current consumption of BLE</description><dc:language>en-US</dc:language><generator>Telligent Community 13</generator><lastBuildDate>Thu, 07 Jun 2018 12:03:45 GMT</lastBuildDate><atom:link rel="self" type="application/rss+xml" href="https://devzone.nordicsemi.com/f/nordic-q-a/35072/estimation-of-battery-life-while-only-advertising" /><item><title>RE: Estimation of battery life while only advertising.</title><link>https://devzone.nordicsemi.com/thread/135143?ContentTypeID=1</link><pubDate>Thu, 07 Jun 2018 12:03:45 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:77d662a3-fc60-4ac0-920b-82c3bba72086</guid><dc:creator>run_ar</dc:creator><description>&lt;p&gt;you are drawing 24.5µA for 0.1 seconds for each advertisement. Doesn&amp;#39;t that mean you are using 2.45µAs per advertisement. Multiply this with 10 advertisement events per second and you are using an amount of energy equal to 24.5µAs per second?&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: Estimation of battery life while only advertising.</title><link>https://devzone.nordicsemi.com/thread/134970?ContentTypeID=1</link><pubDate>Wed, 06 Jun 2018 13:40:34 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:fddfc0dc-20f6-436c-9c4c-ec9000f8d2c9</guid><dc:creator>Jitendra</dc:creator><description>&lt;p&gt;Hi Run_ar..&lt;/p&gt;
&lt;p&gt;I think you ignore the 24,5uA current is average over the one advertising interval, which means each advertising interval consumes 24,5 uA current. So 245uA/sec and 2450uAs per day (24,5uA*10*10)??&lt;/p&gt;
&lt;p&gt;&lt;/p&gt;
&lt;p&gt;Thank you&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: Estimation of battery life while only advertising.</title><link>https://devzone.nordicsemi.com/thread/134937?ContentTypeID=1</link><pubDate>Wed, 06 Jun 2018 12:28:15 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:69212bda-a272-48a6-8c0f-a2c770e70141</guid><dc:creator>run_ar</dc:creator><description>&lt;p&gt;Actually I think you are mixing units in this case. When converting from coulomb to µA the time unit was removed. So 24.5µA doesn&amp;#39;t have a time unit. If you draw this amount of power for 1 second you will get a consumption of 24.5µA/s. Sending 10 advertisements 10 times per day means you are drawing 245µAs per day (it takes ~1 second to send 10 advertisements at 100ms adv int * 10 times per day.).&lt;/p&gt;
&lt;p&gt;So the calculation should look like this: 220 mAh / (0.0245 mA/s) = ~8980 h of continuous advertising. Adjusting to advertising for only 10 seconds per day means you can &amp;quot;advertise forever&amp;quot; (neglecting sleep current and battery discharge current).&lt;/p&gt;
&lt;p&gt;Basically if this is your use case you can neglect the advertisement power consumption and calculate the battery life time based on sleep current and the battery discharge current.&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: Estimation of battery life while only advertising.</title><link>https://devzone.nordicsemi.com/thread/134679?ContentTypeID=1</link><pubDate>Tue, 05 Jun 2018 08:22:52 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:1b675bc7-9e0f-47c2-b519-f23a6922c571</guid><dc:creator>Jitendra</dc:creator><description>&lt;p&gt;Hi Run_ar&lt;/p&gt;
&lt;p&gt;Thank you for yor reply. So following the above formula, I calculated 24.5 uA for one BLE advertising event on nrf52840 pdk running power profiling application(0dBm, 100msec ADV_interval, 1sec &lt;span&gt;APP_ADV_DURATION&amp;nbsp;&lt;/span&gt;). For battery life(220mAh) computation, if wake up the system for&amp;nbsp;&amp;nbsp;&lt;span&gt;APP_ADV_DURATION, and during&amp;nbsp;APP_ADV_DURATION&amp;nbsp; 10 BLE advertising events occur and I&amp;#39;m waking system by button 10 times a day. Then battery life would be in hours:&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span&gt;battery life(hours) = 220mAh/(24.5 uA*10*10) = 89 hours ??&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span&gt;Please correct me if I&amp;#39;m wrong.&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span&gt;&lt;/span&gt;&lt;/p&gt;
&lt;p&gt;&lt;span&gt;Thank you&amp;nbsp;&lt;/span&gt;&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item><item><title>RE: Estimation of battery life while only advertising.</title><link>https://devzone.nordicsemi.com/thread/134671?ContentTypeID=1</link><pubDate>Tue, 05 Jun 2018 08:07:22 GMT</pubDate><guid isPermaLink="false">137ad170-7792-4731-bb38-c0d22fbe4515:50de961a-5d9f-4d33-99c7-9cad997ab66a</guid><dc:creator>run_ar</dc:creator><description>&lt;p&gt;Yes, the total average is for one advertisement interval. So you can multiply this by the number of advertising events to get the total power consumption for advertising.&lt;/p&gt;
&lt;p&gt;Please note that the power calculator is for the nRF52832 so it might deviate from the actual consumption for the nRF52840. I would suggest that you by a&lt;a href="https://www.nordicsemi.com/eng/Products/Power-Profiler-Kit"&gt; power profiler kit&lt;/a&gt; to measure the power consumption for the nRF52840.&lt;/p&gt;&lt;div style="clear:both;"&gt;&lt;/div&gt;</description></item></channel></rss>