https://devzone.nordicsemi.com/f/nordic-q-a/46655/nrf8001-vdd-vs-ivddHi, According to the datasheet: Does this mean that when i change my vdd from 3V to 2V, then the current peaks will be reduced? If so what does this: graph means? This shows me that the as I increase my supply voltage, the supply current reducesen-USTelligent Community 13Mon, 13 May 2019 13:36:13 GMThttps://devzone.nordicsemi.com/thread/186741?ContentTypeID=1Mon, 13 May 2019 13:36:13 GMT137ad170-7792-4731-bb38-c0d22fbe4515:6f767338-05d3-4ab7-a966-349b45476504run_ar<p>The statement is poorly formulated, But please note it is stating that the peak <strong>power</strong> drain will be reduced. When running from the LDO the current drawn will be about the same regardless of voltage. So when running on high voltage it will use more power than needed compared to using the dcdc that lowers the voltage closer to internal the operating voltage of the radio.</p><div style="clear:both;"></div>https://devzone.nordicsemi.com/thread/185314?ContentTypeID=1Mon, 06 May 2019 03:28:42 GMT137ad170-7792-4731-bb38-c0d22fbe4515:89e06f0b-5d86-4407-9cf9-df66073f8d0dBAM<p>What I mean is that the graph shows that increasing the supply voltage decreases the peak currents.</p> <p>But in the statement above, it says that decreasing supply voltage will reduce the peak current.</p> <p></p> <p>Is there a catch between the two reduction of two peak currents with definitely opposite condition?</p> <p></p> <p>Regards,</p> <p>Mon&nbsp;</p><div style="clear:both;"></div>https://devzone.nordicsemi.com/thread/184568?ContentTypeID=1Tue, 30 Apr 2019 12:22:32 GMT137ad170-7792-4731-bb38-c0d22fbe4515:8e2a484a-762a-42c2-9eab-a3ea353e9b6frun_ar<p>The graph shows you the reduction in peak currents compared to running without the dcdc.</p><div style="clear:both;"></div>