https://devzone.nordicsemi.com/f/nordic-q-a/47963/saadc-configure-v-pHello, I am using nrf52840 and I have successfully uploaded the SAADC example. I do not understand why is V(p) = VDD? How can I configure Vp to be equal to voltage that I input to pin AIN0 (P0.02)? The simple example code is in the description. I amen-USTelligent Community 13Tue, 04 Jun 2019 10:32:08 GMThttps://devzone.nordicsemi.com/thread/190724?ContentTypeID=1Tue, 04 Jun 2019 10:32:08 GMT137ad170-7792-4731-bb38-c0d22fbe4515:984630ed-c92f-4de3-b0b2-f5efabd60951JohnnyMcMan<p>Thank you haakonsh</p><div style="clear:both;"></div>https://devzone.nordicsemi.com/thread/190572?ContentTypeID=1Mon, 03 Jun 2019 14:42:58 GMT137ad170-7792-4731-bb38-c0d22fbe4515:d0854550-0f1d-469b-9bf8-8ab20e935969haakonsh<p>It&#39;s because you&#39;ve connected the positive input to VDD:<br />NRF_SAADC-&gt;CH[0].PSELP = SAADC_CH_PSELP_PSELP_VDD &lt;&lt; SAADC_CH_PSELP_PSELP_Pos;&nbsp;</p> <p>See&nbsp;<a href="https://infocenter.nordicsemi.com/topic/ps_nrf52840/saadc.html?cp=3_0_0_5_22_8_17#register.CH-0-7.PSELP">CH[n].PSELP</a>&nbsp;register description.</p><div style="clear:both;"></div>