SAADC CMR

RE: SAADC CMR

Sahar — Wed, 26 Jun 2019 06:06:47 GMT

Thank you ! So it is a real differential ADC.

RE: SAADC CMR

Jørgen Holmefjord — Tue, 25 Jun 2019 08:55:57 GMT

I'm sorry, my previous answer was not entirely correct. I tested this on a DK, and the digital result in differential 10 bit mode will be -511 to +511. This means that Vn can be +/-150mV compared to Vp, within the input range of 0 to VDD. For instance Vp = 2.00 V, Vn = 2.15 V, or Vp = 2.00 V, Vn = 1.85 V.

RE: SAADC CMR

Sahar — Tue, 18 Jun 2019 15:00:32 GMT

What if I have Vp = 2.3V and Vn =2V ? in differential voltage we have 0.3V as in your example, but we have a common mode voltage higher than 300mV, is that acceptable?

RE: SAADC CMR

Jørgen Holmefjord — Tue, 18 Jun 2019 14:46:54 GMT

The input range is per channel. If you for instance, have Vp=450mV, Vn=150mV in 10-bit mode, the digital output will give:

RESULT = (0.450 – 0.150) * (4/0.6) * 2^{(10 - 1)} = 1024

RE: SAADC CMR

Sahar — Tue, 18 Jun 2019 12:59:19 GMT

Hi,

Thank you for your reply,

What is the input range of the differential inputs of the ADC ? in the documentation it is indicated that it can not exceed VDD. If the gain is equal to 4 with internal reference, then the input range calculated based on the documentation is equal to 150mV, is it Vp-Vn that can not exceed 150mV or each one of the inputs ? (the differential input or the common mode input)

If we have a differential voltage less than 150mV and a common mode voltage of 2.5V, can we use the ADC in this configuration (internal reference with gain 4) ?

Thank you in advance

Sahar

RE: SAADC CMR

Jørgen Holmefjord — Tue, 18 Jun 2019 08:40:53 GMT

Hi,

Unfortunately, we do not have measurements of CMRR for the SAADC. However, based on simulations, it is expected to be better than 50 dB.

Best regards,
Jørgen