https://devzone.nordicsemi.com/f/nordic-q-a/51331/where-s-the-leakHi, I&#39;ve been though some power profiling investigation of my application and incorporated the solutions discussed and here and the hardware solution discussed here but I am using a 1Meg Ohm resistor between the VDD rail and the GPIO PIN. The PIN isen-USTelligent Community 13Mon, 26 Aug 2019 19:13:24 GMThttps://devzone.nordicsemi.com/thread/206192?ContentTypeID=1Mon, 26 Aug 2019 19:13:24 GMT137ad170-7792-4731-bb38-c0d22fbe4515:cb6f72b1-c100-4dfb-bb8e-ca7a8ae8993aDW<p>Thank you Stian</p><div style="clear:both;"></div>https://devzone.nordicsemi.com/thread/206021?ContentTypeID=1Mon, 26 Aug 2019 07:35:42 GMT137ad170-7792-4731-bb38-c0d22fbe4515:a3fca7f6-8b19-4cfc-b98e-42b26f51b3b7Stian R&#248;ed Hafskjold<p>Yes, the coin cell on the DK is powering the Atmel chip (Jlink) an lots of other components, so I think the base current is a couple of milliamps, and will drain the coin cell quite fast.</p> <p>The measurements you get from the PPK seems to be good, and you can trust them. You can also double check with this calculator: <a href="https://devzone.nordicsemi.com/nordic/power">https://devzone.nordicsemi.com/nordic/power</a></p> <p>If you want to power only the nRF52, not the whole DK, you can check out my post here: <a href="https://devzone.nordicsemi.com/f/nordic-q-a/20023/how-to-power-the-nrf52-chip-as-standalone-without-the-dk">https://devzone.nordicsemi.com/f/nordic-q-a/20023/how-to-power-the-nrf52-chip-as-standalone-without-the-dk</a></p><div style="clear:both;"></div>https://devzone.nordicsemi.com/thread/205721?ContentTypeID=1Fri, 23 Aug 2019 01:16:57 GMT137ad170-7792-4731-bb38-c0d22fbe4515:50d9c245-752b-44a9-a3f3-faa1d47b830fDW<p>I&#39;m getting a 2.88V drop over the 1Meg Ohm resistor giving a calculated current of 2.88uA.&nbsp;</p><div style="clear:both;"></div>