How to get full Service UUID from given BASE UUID

[davidm]

Hi all

I am trying to pair nrf52840 (as a central) with ESP32 (as peripheral).

 Now I want to get the service uuid so that i can pass to advertising service in ESP32 code.How do I get the full-service UUID, I see that in the ble_lbs_c service  UUID is declared as 0x1523 characteristic  UUID as 0x1525 and LBS_UUID_BASE {0x23, 0xD1, 0xBC, 0xEA, 0x5F, 0x78, 0x23, 0x15, 0xDE, 0xEF, 0x12, 0x12, 0x00, 0x00, 0x00, 0x00}

I tried to pass the service uuid as #define SERVICE_UUID   "23151212EFDE1523785FEABCD1" on ESP32 program but that didnt work. What is the exact order of the UUID? If you need  details on esp32 code here is the example esp32 program

I am using ble_app_blinky_c example on nrf52840.

Thank you in advance

[davidm]

Hi Edvin

My mistake, I meant to say ...it does get inside name_filter_enabled but  adv_name_compare(p_adv_report, p_scan_ctx)is always false.

It was a copy/paste  error.

[Edvin]

Ok. Then you need to debug it when you know it is the correct device, and find out why it returns false.

One hint when debugging is to apply a second filter before adv_name_compare is called, if you know something else about this specific device. If you know that the address starts with e.g. 0xb5, then you can do a check:

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if(p_adv_report-> ... .addr[0] == 0xb5)

{

adv_name_compare();

}

XXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXXX

if(p_adv_report-> ... .addr[0] == 0xb5)
{
    adv_name_compare();
}

Why does it not return true?