How do I power off the UART

[Timothy]

I have a nRF9160 board that is running off batteries. I need to conserve power and I would like to power off the UART. In the field I do not need any printouts or listening to keystrokes. How do I completely power off the UART? There will not be a terminal connected in the field. The terminal would only be used at the factory for configuring the boards and saving the configuration to Flash.

[Achim Kraus]

Hm, not sure, maybe it was somehow mixed up:

If "CONFIG_SERIAL=n" is used, then you don't need the "power_manager" stuff.

So the part:

#if 1
/*Option 3: by chosen node*/
#define MY_SERIAL DT_CHOSEN(zephyr_console)
const struct device *uart_dev = device_get_binding(DT_LABEL(MY_SERIAL));
pm_device_state_set(uart_dev,PM_DEVICE_STATE_OFF);
#endif

must/may be switched off by "#if 0".

If "CONFIG_SERIAL=y" is used, then you may use the "power_manager" stuff. But don't call "pm_device_state_set(uart_dev,PM_DEVICE_STATE_OFF);" unconditional. I would always guard that with

if (device_is_ready(uart_dev)) {
  pm_device_state_set(uart_dev,PM_DEVICE_STATE_OFF);
}

that doesn't crash, even if "uart_dev" is NULL.

[Timothy]

Achim

I used the second method with CONFIG_SERIAL=y and pm_device_state_set(uart_dev,PM_DEVICE_STATE_OFF); it does disable the UARt and does not crash. The production application continues to run. Thank you very much. you can close this ticket.

[Achim Kraus]

> you can close this ticket.

I'm an other user, it's up to you to click "Verify Answer" ;-)