If you look at the circuit of the PCA10040, it uses a 32Mhz 12pF crystal.
C1 and C2 of the crystal are 12 pF.
However, you say to use this formula: C1 = C_L * 2 - 4pF.
12pF*2 - 4pF = 20pF
Why use 12 pF instead of 20 pF?
If you look at the circuit of the PCA10040, it uses a 32Mhz 12pF crystal.
C1 and C2 of the crystal are 12 pF.
However, you say to use this formula: C1 = C_L * 2 - 4pF.
12pF*2 - 4pF = 20pF
Why use 12 pF instead of 20 pF?
In the component parameters, the crystal oscillator also has load capacitance. Take PCA10040 as an example, the internal load capacitance of 32Mhz crystal oscillator is 8pF. Do you consider the internal load capacitance of crystal oscillator in your calculation?
Thank you.
I was looking at the wrong datasheet.
No worries. Then I'll close the case.
No worries. Then I'll close the case.