Hello.
I am trying to boot the nRF54L15DK from an external power source.
Referencing this page, I supplied 3.3V to P6, but the SoC could not boot.
The 'VDDM_nRF' through-hole connector on the board is showing 3.3V, and the 'VDD_nRF' is showing 2.5V.
The 'VDD_nRF' fluctuates slightly with each power-up.
However, when 5V was further supplied from the USB connector J3, the SoC could boot.
Both 'VDDM_nRF' and 'VDD_nRF' are showing 3.3V.
After the SoC has booted, it remains running even after the USB is removed.
The 'VDD_nRF' maintains 3.3V.
The 5 V domain must be supplied from the debugger USB connector J3 to ensure the pins of the nRF54L15 System on Chip (SoC) are not connected to unpowered devices.
Since only the nRF54L15 is supplied from this source, it is important that the 5 V domain is supplied from the interface debugger USB connector J3 to ensure the pins of the nRF54L15 are not connected to unpowered devices.
Does this sentence mean that even when only the SoC boots, power from the USB is always required?
Or is there an error in the procedure or settings when booting using only the power supplied from P6?
The program uses the Bluetooth Mesh sample.
I am determining whether the SoC has booted using the Device Manager App or the nRF Connect App.
Thanks for reading.
a.da
