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Button 4 to enter the DFU mode?

Hello, I am evaluating ways to enter the DFU mode when application is corrupted (i.e. it does not reach the code for entering bootloader).

The documentation states that the DFU mode is started when "Button 4 is pressed when starting the device".

Does this mean that the bootloader binary blob itself checks whether GPIO P0.20 (Button 4 at PCA10028) is low during startup? If so, does it use any other GPIO pins (i.e. for LEDs)?

Alternatively, is there any other way to start bootloader after successfully loading "corrupted" application?

Thank you,

Adam

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