Hello,
I want to use nRF52832 at 2V. But I am not sure what would be the current consumption of radio during transmission and reception with DCDC regulator on. In datasheet radio current consumption is mention at 3V. Whether it will be high as compared to VDD at 3V? Is it efficient to use nRF52832 at 2V VDD ? I want to use nRF52832 with less operational voltage and low current consumption. what would be good voltage supply range?
Thank you
Hi Swapnil
To realize how DCDC works and LDO, look at the answer on this thread. Current consumption from the power supply is always the same when using LDO, but when using DCDC the current consumption decreases as you increase the supply voltage.
The nRF52832 LDO or DCDC provide a system power of 1.3V. When looking at e.g. the radio RX current consumption, there is about 50% current consumption decrease when using DCDC at 3V supply voltage, compared to DCDC. I suspect there is more or less linear decrease in current consumption when using DCDC from 1.3V, as shown on this graph. This graph might not be entirely accurate, perhaps it is linear from 1.4V or 1.5V, but at least it demonstrates the behavior.
Update 25.8.2016 Perhaps better approximation of DCDC current consumptioin than the linear approximation above is shown in the graph below.
The formula that I have used to generate the graph is:
I_DCDC = (I_LDO * U_system / VDD) + I_DCDC_enabled
where:
To generate the graph above I have used the following parameters for current consumption of the nRF52832 radio RX:
