ili9325 drive 8 bit interface with nrf51822

Question

I have this 2,4" TFT Display with a IL9325 driver! I need to implement a 8bit 8080 Parallel interface. 
 image description 
 This is my 8 bit write function: 
 // Write 8-bit value data lines 
 void write8(uint8_t data) { 
nrf_gpio_pin_write(pinDataHold.TFT_D7, ((data & 10000000) >> 7)); 
nrf_gpio_pin_write(pinDataHold.TFT_D6, ((data & 01000000) >> 6)); 
nrf_gpio_pin_write(pinDataHold.TFT_D5, ((data & 00100000) >> 5));
nrf_gpio_pin_write(pinDataHold.TFT_D4, ((data & 00010000) >> 4)); 
nrf_gpio_pin_write(pinDataHold.TFT_D3, ((data & 00001000) >> 3)); 
nrf_gpio_pin_write(pinDataHold.TFT_D2, ((data & 00000100) >> 2)); 
nrf_gpio_pin_write(pinDataHold.TFT_D1, ((data & 00000010) >> 1)); 
nrf_gpio_pin_write(pinDataHold.TFT_D0, data & 00000001); 
WR_STROBE();
nrf_delay_ms(1); 
}
 
 ======================================== 
 Is there any problem with this function? What I do is write the values to the pins and then make the LCD read the pins.

SL06 · Answer

This post is old but for the next user... The above approach is technically correct . You have to put the CS and WR bytes low before sending the data to the TFT and high, after. Using NRF_GPIO OUTCLR and OUTSET is a better approch. They set selected pins of GPIO register in one command.

uint8_t data = (c >> 2) | ((c & 0b00000011) << 6); // If needed, teorganise your bytes order corresponding to the TFT pin out if need. Here is for pin D0.. D7 => Pin 19, 20, 13, 14, 15,16, 17,18

NRF_GPIO->OUTCLR = (0xFF << 13); //Erase the region, OUTCLEAR Write: writing a '1' sets the pin low; writing a '0' has no effect

NRF_GPIO->OUTSET = (data << 13); //Send data on selected pin, OUTSET Write: writing a '1' sets the pin high; writing a '0' has no effect