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Sleep Immediately after Beacon Advertisement

I'm using the following code to make the beacon sleep:

static void on_ble_evt(ble_evt_t * p_ble_evt)
{
    uint32_t        err_code;
    switch (p_ble_evt->header.evt_id)
    {
        case BLE_GAP_EVT_CONNECTED:
        {
            break;
        }
        case BLE_GAP_EVT_TIMEOUT:
        {
            if (p_ble_evt->evt.gap_evt.params.timeout.src == BLE_GAP_TIMEOUT_SRC_ADVERTISING)
            {
                sd_ble_gap_adv_stop();
                ble_fsm_set_state(Ble_Fsm_State_Idle);
            }
            break;
        }
        default:
        {
            break;
        }
    }
}

Once the state is set to idle, the nrf51 chip goes to sleep and the current draw drops to the order of uA. My only problem here is that the minimum timeout value is 1s and this means that the chip is burning power for 1s. Ideally, I would like the beacon to just advertise once and then go to sleep immediately. What is the best way to do this? Adding a synchronous delay of 5 ms? Any callback that I can use instead?

Parents
  • What do you mean by "sleep"? I assume that nRF5x chip is going to POWER ON SLEEP (wait for event/interrupt) always when nothing is running on MCU so even between adv. events. If you mean POWER OFF state then sure you can do it but no BLE activity can be running during that time, you need to manage wake-up by some external GPIO interrupt line (button or some RTC capable chip if you expect to wake-up periodically).

  • Super weird, because if I call sd_app_evt_wait() before sd_ble_gap_adv_stop(), then it consumes 20 mA. But if I call the two functions in the opposite order, I get a sleep current of a few uA. Definitely going to give radio_notification a shot. Thanks for the super quick responses! You've been a huge help!

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