Hi,
I have a question regarding the width of the RF traces on the NRF24L01+. From the gerbers I notice the width is approximately 0.5mm and the separation to the closest ground plane is approximately 1.2mm. What is the purpose of this and how does this achieve a 50 Ohm impedance?
Would it not be better to use a Coplanar Waveguide with trace width 1.1mm, plane clearance of 0.2mm and a distance from top to bottom layer of 1.55mm for a 2-layer board? Please advise as soon as possible.
Thanks,
Alex