nRF9160 SRAM Partition changes

Question

Hello, 
 I would like to modify the current default SRAM partition from 64k (secure), 64k (bsd), 128k (non-secure). I would like to change it as follows; 8 k (secure), 8k (bsd), 240k (non-secure). The secure_boot application is only using around 4k now, so 8k is more than enough. Will the bsd be ok at 8k? What other potential problems should I look out for? 
 Thanks, 
 JL

Martin Lesund · Answer

Hi JL, 
 Update 20.01.2020: 
 Check the updated BSDLIB documentation for the latest information. 
 
 "The secure domain memory is divided into segments of 8 KB RAM blocks. Because the size of the BSD library block is 0xC020 bytes, it is not aligned to full 8 KB blocks. It occupies six blocks and a small part of a seventh block. 
 The leftover memory in that seventh block (8160 bytes, starting at address 0x2001 c020) is configured as non-secure, but it can be used by the application."

Old answer: The BSD Library has an absolute position and is fixed at starting address 64K and size of 64K (0x20010000 &ndash; 0x2001FFFF). 
 This cannot be moved. 
 However, all other partitions might be moved. 
 Note: The BSD memory always has to be Non-Secure configured. 
 
 You can find the "Default flash planning" in the file: [/ ncs/zephyr/boards/arm/nrf9160_pca10090/ nrf9160_pca10090_partition_conf.dts ] 
 There it's also documented that " 64 kB SRAM reserved for and used by the BSD socket library. " 
 
 Best regards, Martin L.

nRF9160 SRAM Partition changes

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