Same button used for LED on and OFF using External Interrupt

[gain]

Hello ,

I am new to nrf52832

i am using external interrupt for led on and off 

here the problem is when i press the button 1 led will turned on if i press the same button 1 led will be turned off 

kindly provide solution 

Thank you

[gain]

my question is how to turn off led using same button

[Patrick]

Sounds like you probably want to use nrf_gpio_pin_toggle(pin) in your interrupt handler. You haven't given much detail so it is hard to say what you would need to change.

[gain]

this my code until we press the same button again led will be on state

void in_pin_handler(nrf_drv_gpiote_pin_t pin, nrf_gpiote_polarity_t action)
{

switch(action)
{
case NRF_GPIOTE_POLARITY_TOGGLE:

{
if(nrf_gpio_pin_read(PIN_IN) == BUTTON_PRESSED)
{
nrf_drv_gpiote_out_set(PIN_OUT);

}
else
{
nrf_drv_gpiote_out_clear(PIN_OUT);
}

break;
}


default:
//do nothing
break;

}

}





/**
* @brief Function for configuring: PIN_IN pin for input, PIN_OUT pin for output,
* and configures GPIOTE to give an interrupt on pin change.
*/
int main(void)
{
nrf_gpio_cfg_input(BUTTON_1, NRF_GPIO_PIN_PULLUP);

ret_code_t ret_code;

// Initialize the GPIOTE Peripheral
ret_code = nrf_drv_gpiote_init();
APP_ERROR_CHECK(ret_code);

// Configure LED_3 pin as output
nrf_drv_gpiote_out_config_t led_config = GPIOTE_CONFIG_OUT_TASK_LOW;

// Initialize LED_3 pin as output
ret_code = nrf_drv_gpiote_out_init(PIN_OUT, &led_config);
APP_ERROR_CHECK(ret_code);



// Configuration for Interrupt Pin
nrf_drv_gpiote_in_config_t config =
{
.sense = NRF_GPIOTE_POLARITY_TOGGLE,
.pull = NRF_GPIO_PIN_PULLUP ,
.is_watcher = false,
.hi_accuracy = false
};

// Initialize Interrupt Pin
ret_code = nrf_drv_gpiote_in_init(PIN_IN, &config,in_pin_handler);
APP_ERROR_CHECK(ret_code);

// Enable Interrupts from interrupt pin
nrf_drv_gpiote_in_event_enable(PIN_IN,true);


while (true)
{
// Do nothing.
}

}