Hi Sir,
If we would like to supply the external device through VDD = 1.8V when VDDH = 2.5V.
What is power efficient in nRF52840 when VDD = 1.8V when VDDH = 2.5V?
Thank you.
BRs, Han
Hi Sir,
If we would like to supply the external device through VDD = 1.8V when VDDH = 2.5V.
What is power efficient in nRF52840 when VDD = 1.8V when VDDH = 2.5V?
Thank you.
BRs, Han
Hi Han
I'm struggling to understand what exactly you mean, but I assume you are referring to what regulator configuration will be most efficient in your scenario (Please specify if this is not the case). If you enable the DCDC regulator the PMU (Power Management Unit) will automatically switch between what regulators to use to be the most power efficient.
Best regards,
Simon
Hi Simon,
Sorry to make you confuse. We just want to know the power-efficiency ratio for internal LDO and DCDC mode
The power-efficiency ratio = Pout/Pin
If the VDDH = 2.5V, and VDD=1.8V
could we say the power-efficiency ratio is 1.8/2.5=72%?
Thank you.
BRs, Han
Hi Simon,
Sorry to make you confuse. We just want to know the power-efficiency ratio for internal LDO and DCDC mode
The power-efficiency ratio = Pout/Pin
If the VDDH = 2.5V, and VDD=1.8V
could we say the power-efficiency ratio is 1.8/2.5=72%?
Thank you.
BRs, Han