Hardfault

[Nasib]

Hi. 

I just put this on my main code: 



uint32_t pg_size,* addr,pg_num,numero_guardado_memoria=0;

pg_size = NRF_FICR->CODEPAGESIZE;
pg_num = NRF_FICR->CODESIZE - 1;

addr= (uint32_t *)(pg_size * (pg_num+1));
if((uint32_t)*(addr)=='D'){
     addr=(uint32_t *)(pg_size * (pg_num + 2));
     numero_guardado_memoria=(uint32_t)*(addr);
}

to simply read what is stored in a memory position ... and ones i debug the program, just after the if.. it lauch me a hardfault...

i can't understand. 

please i need your help. 

[Dmitry]

Hi, 

pg_size * (pg_num+1)  will point to a non-existing byte right after your flash memory, it's no wonder that you're catching a hardfault..

[Nasib]

How can i acces to the first 32bits word after de code ? and the second one.. and so on ? 
 
I need to storage and read info from sensors to de flash.. 

Thanks a lot.. 

[Dmitry]

Your flash is from address 0 to (NRF_FICR->CODESIZE * NRF_FICR->CODEPAGESIZE - 1), there's no memory after it. If you need to allocate some area of flash for your data, you have to change code size in your project settings (that is IROM1 in Keil) . Decrease this value, for example, by (pagesize*2), and you'll have two pages for data at the end of flash: (pg_num-1) and (pg_num-2).

[Nasib]

Could you explain me a little bit what is a page and how big in it is ? 

Thanks a lot Dmitry (really)

[Dmitry]

You can read documentation about how flash memory works.

Flash page size depends on chip: nrf51 - 1024 bytes, nrf52 - 4096 bytes.