calculate daily current consumption given the advertising/non advertising test value

[kfcube]

51822+LIS3DH

I have tested my board and got the current consumption value. I use slow advertising only and the interval is 2 seconds. Follow is the result:

1. advertising. 0.03MA for each advertising

2. when not advertising. 0.002MA. 

Above value are under the case that the lis3dh sensor is power off. I need to test the daily current consumption when the lis3dh sensor is not using. Here is my way of calculating:

1. non-advertising, 24 hours * 0.002MA = 0.048MA

2. advertising. I assume the advertising time is 1ms. So 24 hours * (0.03 *1 ms / 2000ms)  / 2 = 0.00018MA 

My questions are:

1 .Is the 1ms advertising time correct assumption?  I don't know where to get this info and I just made a guess. The advertising payload is low, only one service UUID, nrf name, no appearance, 

2. Is the way my calculation algorithm correct? If not ,what's the right way to calcualte?

Thanks,

[Simonr]

Hi

You're absolutely correct, I'm sorry I didn't notice that you were using the nRF51. If you'd like measurement as accurate as possible, I suggest getting a Power Profiler Kit and a DK in order to measure the current consumption of your device with our Power Profiler app in nRFConnect. 

If you want more of an estimate instead I still suggest looking at the Online Power Profiler, as the outline of one advertisement will be similar. One advertising event will last for ~3.5ms each time it advertises, so you have to put that into consideration. Other than that, I don't think your estimate is off by that much, but I would suggest doing some actual measurements.

Best regards,

Simon

[kfcube]

got it, thanks a lot