Hello,
I am looking at the schematic for the nRF5340 DK and see that there are no external load capacitors for the 32 kHz crystal which has C_L = 9 pF. Therefore, we are relying on the nRF5340 internal load capacitor feature through firmware. Looking here, I see that it is set to 6 pF by default. Looking here in the PS, I see that C_pin is either 6, 7, or 9 pF if you have the internal capacitors enabled and given that we are setting it to 6 pF, I assume this means that C_pin = 6 pF. Now assuming that C_pcb = 1 pF and C1 = C2 = 0 (because there are no external capacitors), using the formula here, I find that C1' = C2' = 7 pF and C_L is therefore 3.5 pF which does not equal the C_L of the crystal (9 pF). Even if I set the internal load capacitor register to the maximum of 9 pF, I only get C_L = 5 pF. How should this register be set properly to prevent the need for external load capacitors? Seems I am missing something in the calculation.
Regards,
Akash Patel