Application with SoftDevice have to put at address 0x14000?

[zhijun lu]

I put the boot loader at 0x3a800 and the application at 0x27400. the region from 0x14000 to 0x27400 is all blank (0xff). also

nrfjprog --memwr 0x10001014 --val 0x0003a800

The boot loader only does one thing, jump to the application at 0x27400 using sd_softdevice_forward_to_application();

I found the application at 0x27400 works but didn't do advertising, but if move the application to 0x14000, then it does advertising and everything works fine.

I am wondering do we have to put the application at 0x14000 if using SoftDevice? or SoftDeviice won't pass the interrupt to App. Or Did I miss some thing to enable SoftDevice pass interrupts to the application at 0x274000?

thanks,

[Ole Morten]

As Asbjørn says, the application has to be located at 0x14000 when using the S110. I would not recommend you to ever erase UICR while in the field, since this may leave the device permanently unusable if power is lost at a bad time.

However, this reply contains a little information that may be helpful for implementing a scenario similar to the one you request.

Edit: Sorry, didn't notice that you were the one asking the other question. However, there isn't really any magic way to achieve exactly what you want. When the S110 is programmed it will set CLENR0 to 0x14000, and to change that you have to first erase UICR. As I mention above, this is dangerous to do in the field, since a power loss right after having erased it will brick your device.

Edit 2: Another option could be to put your bootloader at 0x14000, and make it forward the interrupts manually to whatever application is running. This would increase the interrupt latency a little, but would avoid any flash write or erases while running. This bootloader implements this scheme, so it might be useful as inspiration.

[Guest]

Hi Ole,

I just copied App2 application vector to 0x14000, then interrupts passed to App2. It looks work fine.

thanks,