Init more than one PWM

Question

I would like to use 3 PWM for controling RGBs. I use a softdevice because I want to control the pwm trough the MCP. But for now I just want to get it work to initialize these 3 pwms. 
 If I init one PWM everything works. When I try to init a second PWM, the first pwm will also not work. 
 Here the Init for the 2 PWMs: 
 static volatile bool ready_flag0;
static volatile bool ready_flag1;

APP_PWM_INSTANCE(PWM0,0);
APP_PWM_INSTANCE(PWM1,1);

static void pwm0_ready_callback(uint32_t pwm0_id)
{
 ready_flag0 = true;
}

static void pwm1_ready_callback(uint32_t pwm1_id)
{
 ready_flag1 = true;
}

static void PWMinit(void)
{
 app_pwm_config_t pwm0_cfg = APP_PWM_DEFAULT_CONFIG_1CH(2000000,22);
 pwm0_cfg.pin_polarity[0]	= APP_PWM_POLARITY_ACTIVE_HIGH;
 app_pwm_init(&PWM0,&pwm0_cfg,pwm0_ready_callback);

 app_pwm_config_t pwm1_cfg = APP_PWM_DEFAULT_CONFIG_1CH(1000000, 23);
 pwm1_cfg.pin_polarity[0]	= APP_PWM_POLARITY_ACTIVE_HIGH;
 app_pwm_init(&PWM1,&pwm1_cfg,pwm1_ready_callback);
}

static void PWMstart(uint8_t pwm_number)
{
 switch(pwm_number)
 {
 case 0: nrf_drv_gpiote_out_task_enable(22);
 app_pwm_enable(&PWM0);
 while (app_pwm_channel_duty_set(&PWM0, 0, 50) == NRF_ERROR_BUSY);
 break;
	
 case 1: nrf_drv_gpiote_out_task_enable(23);
 app_pwm_enable(&PWM1);
 while (app_pwm_channel_duty_set(&PWM1, 0, 50) == NRF_ERROR_BUSY);
 break;
 }
}
 
 And in the main: 
 PWMinit();
PWMstart(0);
PWMstart(1);
 
 What is wrong with the initialization for the second pwm?

Krzysztof Chruscinski · Accepted Answer

Hi, 
 some hints: 
 
 TIMER0 is used by SoftDevice so it will generate conflict creating instance using TIMER0 (APP_PWM_INSTANCE(PWM0,0);), 
 nrf_drv_gpiote_out_task_enable(x); calls are redundant. 
 would be good to check return value of app_pwm_init() 
 
 However, I don't know yet how it can give the behavior you've described.

Init more than one PWM

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