5V nRF52833 I2C connection to 1.8V device

[Kaveh.M]

Hi, 

I have connected my nRF52833 chip to a sensor. 

nRF52833 is supplied at 5V. The sensor supply voltage is 1.8V.

My sensor communicates with nRF52833 on I2C bus. I2C bus of sensor is connected to 1.8V by pull up resistors. Does this system work fine or I still need a level shifter for I2C proper functionality? 

See below diagram.

[Vidar Berg]

Hi,

Even if you can get reliable communication, 5v may damage the inputs on the sensor. For comparison, the nRF52833 does not support more than VDD + 0.3v on its GPIO pads (Absolute maximum ratings). But have you measured 5 V on the i2c lines? As you may know, the IO voltage on the nRF is not controlled by the VDDH input but by the output of the REG0 regulator.

The output voltage of REG0 can be adjusted through the non-volatile REGOUT0 register in UICR. It defaults to 1.8v after a full chip erase.

Best regards,

Vidar

[Kaveh.M]

I have not measured anything yet. I am in the design stage. 

I want to know if the architecture that I shared work, and if not, what needs to be added to my design. 

So you mean when I get a bare erased nRF52833 chip, its default I2C bus voltage is 1.8V and my design can work without any issues? 

[Vidar Berg]

I don't see any problems with this design. Just note that you need to select a configuration that supports "VDDH/high voltage mode" for your board design if you want to supply the chip directly from a 5v source.

Reference circuitry

[Kaveh.M]

My design is not working as expected meaning that the voltage on my I2C bus is not 1.8V but it is leaning toward 3V. How can I set I2C bus voltage to 1.8V (or 3V) using  REGOUT0 register in UICR? 

Is there a sample code for it? 

Thanks

[Kaveh.M]

I have used this below line in main()  to set my I2C bus level to 1.8V: 

NRF_UICR->REGOUT0 = UICR_REGOUT0_VOUT_1V8;

But still seems my I2C line is at 3V. Please note that my processor supply voltage is 3.3V.