How can I calculate the maximum throughput for an application running on the nRF51822 and the S110, when connecting to different kind of Central devices?
How can I calculate the maximum throughput for an application running on the nRF51822 and the S110, when connecting to different kind of Central devices?
Hi, I'm still confused about few things.
How can I calculate the maximum throughput for a ble link between peripheral and central device ? I'm sending a packet (20bytes = 160 bits) every 40ms until send a total of 1000 packets.
R = (160*1000)/40s = 4000bps => 3.9kbps
That is a correct way for calculate throughput for ble ?? and the max and min connection interval ? at this moment my parameters are:
DEFAULT_DESIRED_MIN_CONN_INTERVAL 32; // 40ms
DEFAULT_DESIRED_MAX_CONN_INTERVAL 64; //80ms
How do these values interfere with my calculations? I dont understand your examples because my propose is calculate throughput after sending 1000 packets.
Thank you for everyone and please, help me :)
Regards
As stated above, the throughput is dependent on the connection interval, and you can take a look at this question for an explanation of connection parameters: https://devzone.nordicsemi.com/index.php/what-is-connection-parameters
If you want to transfer data every 40 ms, you should use a connection interval of 40 ms. For a link with a connection interval of 40 ms, max throughput will be 6 * 20 B * 1/(0.040 s) = 3 kB/s if your devices are capable of transferring six packet per interval and 1 * 20 B * 1/(0.040 s) = 0.5 kB/s if you transfer one packets per interval.
As stated above, the throughput is dependent on the connection interval, and you can take a look at this question for an explanation of connection parameters: https://devzone.nordicsemi.com/index.php/what-is-connection-parameters
If you want to transfer data every 40 ms, you should use a connection interval of 40 ms. For a link with a connection interval of 40 ms, max throughput will be 6 * 20 B * 1/(0.040 s) = 3 kB/s if your devices are capable of transferring six packet per interval and 1 * 20 B * 1/(0.040 s) = 0.5 kB/s if you transfer one packets per interval.